Question

20 An
A cracker rocket is ejecting gases at a rate of
0.05 kg/s with a velocity 400 m/s. The accelerating
force on the rocket is
(1) 20 dyne
(2) 20 N
(3) 200 N
(4) Zero​

Answer 1

20answer

Explanation:

cracker rocket gases rate =0.05kg

velocity of cracker rocket =400m/s

accelerating force on the rocket = 0.05kg×400m/s

= 20N answer

Answer 2

Answer:

The accelerating force on the rocket will be 20 N.

Explanation:

Given;-

   Rate at which fuel is burning, dm/dt = 0.05 kg/s

     Velocity of gases, v = 400 m/s

Let the accelerating force on the rocket be 'F'

We know by formula that;-

              F = v dm/dt

Putting the given values in the formula, we get;-

               F = 400 × 0.05

               F = 20 N

Hence, the accelerating force on the rocket will be 20 N.

Hope it helps! ;-))