Question

20
An aeroplane is flying in horizontal
direction with a velocity of 540
km/hr at a height of 2200 m. When it
Is vertically above the ground, a body
is dropped from it. What is the time
taken and how much horizontal
distance covered when the body hits
the ground. Neglect air resistance."
25 sec, 3156 m
21 sec, 3176 m
O 28 sec, 3166 m
30 sec, 3186 m​

Answer 1

$\color{red}\huge{\underline{\underline{GIVEN\dag}}}$

• An aeroplane is moving with 540km/hr and 2200m above the ground.
• Height(h)-2200m
• Velocity(v)-540km/hr
• v-150 m/s

$\color{red}\huge{\underline{\underline{SOLUTION\dag}}}$

We know that;

$\color{blue}\boxed{Time(of\: flight\: of\: object)=\sqrt{\frac{2h}{g}}}$

Where,

• h-height
• g-accelaration due to gravity($10m/s^{2}$

$Time=\sqrt{\frac{2(2200)}{10}}$

$Time=20.9sec$

We also know that;

$\color{blue}\boxed{R(distance)=v\sqrt{\frac{2h}{g}}}$

$R=150×20.9$

$R=3146m$

HOPE THAT HELPS!!

(pls check the calculations but this is the method)