Physics, asked by wanibilal096, 10 months ago

20. An air capacitor of capacitance 3 uF 1
is charged to 400V. If a medium with
dielectric constant 3 is inserted
between its plates and the potential is
raised again to the same value, then
the amount of energy stored will be​

Answers

Answered by umeshksuman
2

Explanation:

Initial charge q

i

=CV=10(12)=120μC.

After filled with dielectric liquid the charge q

=C

V=KCV=5(10)12=600μC

The (additional) charge that flows now from battery to the capacitor =q

f

−q

i

=600−120=480μC

.

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