Question

20. An organic compound has the composition :
C=58.5%, H=4.06% , N=11.4% and O=26.0%. Determine the empirical formula of the compound​

Answer 1

Answer:Empirical formula is C6H5N1O2

Explanation:

Answer 2

Answer:

The emperical formula of the given compound is C6H5NO2.

Explanation:

• We can say that the empirical formula of a chemical compound is the simplest whole number ratio of atoms present in the substance, as defined in chemistry.
• The empirical formula of sulphur monoxide, or SO, as well as the empirical formula of disulfur dioxide, S2O2, are basic examples of this notion.

Carbon :

Element - C

% composition - 58.55

Atomic mass - 12

% atomic mass - 4.8291

Simple ratio - 6.01

Whole number - 6

Hydrogen :

Element - H

% composition - 4.05

Atomic mass - 1

% atomic mass - 4.05

Simple ratio - 4.99

Whole number - 5

Oxygen :

Element - O

% composition - 26.04

Atomic mass - 16

% atomic mass - 1.6265

Simple ratio - 2.066

Whole number - 2

Nitrogen :

Element - N

% composition - 11.36

Atomic mass - 4

% atomic mass -0.8111

Simple ratio - 1

Whole number - 1

Therefore according to the above records, empirical formula is C6H5NO2 .

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