Math, asked by zainzed19, 7 months ago

20.
biased tetrahedral die with faces labelled 1, 2, 3 and 4 is rolled once.
The chance of getting a 3' is twice that of getting a '1'. The chance of getting
a 2' is thrice that of getting a '3'. There is an equal chance of getting a '2' and a
'4'. Find the probability of getting a prime number.​

Answers

Answered by amitnrw
0

Given :     The chance of getting a 3' is twice that of getting a '1'. The chance of getting  a 2' is thrice that of getting a '3'. There is an equal chance of getting a '2' and a  '4'.

To find : probability of getting a prime number.​

Solution:

Let say Probability of getting 2 & 4 Each  =  6P

The chance of getting  a 2' is thrice that of getting a '3'

=> Probability of getting 3  = 6P/3 = 2P

The chance of getting a 3' is twice that of getting a '1'.

=> Probability of getting 1 = 2P/2 = P

P + 2P + 6P  + 6P   = 15P   = 1

=> P = 1/15

probability of getting a prime number.​  

Prime numbers 2 & 3

6P + 2P  = 8P  = 8/15

8/15 is the probability of getting a prime number.​  

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