Question

20 cc of 1N HCL , 30 CC of 0.5N H2SO4 and 50CC of 0.2 N HNO3 are mixed together .What will be the normality of the final solution ?

Answer 1

Answer:

Meq= N × V

where Meq is the equivalent molarity

N is normality of the solution

V is volume of solution

Applying the formula to each of the solution separately

1) HCl

Meq= 1×5 = 5M

2) H2SO4

Meq= 1/2 ×20=10 M

3) HNO3

Meq= 1/3 × 30 = 10M

For total solution

Meq = M1 + M2 + M3

Meq = 5+10+10 = 25 M

and volume = 1000 mL

Thus applying the same formula

Meq= N × V

25 = N× 1000

N= $$\dfrac{25}{1000} N

= 40N

Thus normality of the solution would be

40N.

Explanation:

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