Question

20. Consider the reaction:
H.SO, (aq) + Snº(aq) +H2O(l) → Sn²+ (aq) +HSO (aq)+3H(aq)
Which of the following statements is correct?
(1) Sn" is the oxidizing agent because it undergoes
oxidation
(2) Sn4+ is the reducing agent because it undergoes
oxidation.
(3) H,SO, is the reducing agent because it undergoes
oxidation
(4) H,SO, is the reducing agent because it undergoes
reduction.​

Answer 1

H2SO4 is a reducing agent undergo oxidation reaction.

Option (3) is correct.

Explanation:

• H2SO4 is the reducing agent because it undergoes oxidation.
• Reducing agent is a specie or reactant that loses or donates its electrons to the other specie or recipient in a reduction or chemical reaction.
• Oxidation is the loss of electrons and the oxidizing agents is that specie that removes an electron from other specie during a chemical reaction or redox reaction.

Answer 2

$H_{2} SO_{4} (aq) + Sn_{(aq)} +H2O(l) -> Sn^{2} + (aq) +HSO (aq)+3H(aq) is$

3.)$H_{2} SO_{4}$ is a reducing agent undergo oxidation reaction.

Explanation:

$H_{2} SO_{4}$ is the reducing agent because it undergoes oxidation.

• Reagent is a component or solvent that forfeits an electron to an electron recipient in a reduction ox chemical response.
• A reducing agent is thus corrupted when it misses electrons in the reduction reaction. Lessening agencies "reduce" corroding agents.
• Oxidation is the casualty of electrons during a response by a molecule, particle, or ion. Oxidation occurs when the oxidation state of a unit, particle or ion is developed.

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