20 cylindrial PILLARS ARE TO BE CLEANED IF THE DIAMETER OF EACH IS 0.5m and the height is 4m what will be cost of cleaning at the rate of rs 2.5 per m²
Answers
Answered by
18
Answer:
Cleaning means wiping, right?
So,
In each pillar,
diameter, d= 0.5m
∴radius, r= d÷2 = 0.25m
height, h= 4m
For wiping the cylindrical pillars, we need to wipe the curved surface.
∴Curved surface area of 1 pillar= 2πrh
= 2 x 22/7 x 0.25 x 4 m²
= 2 x 22/7 x 25/100 x 4
= (22/7 x 2) m²
∴Curved surface area of 20 such pillars= 20 x (22/7 x 2) m²
≈125.71 m² (ANS)
Answered by
1
Answer:
Hey , here is your answer step-by-step :
Step-by-step explanation:
In each pillar,
diameter, d= 0.5m
∴radius, r= d÷2 = 0.25m
height, h= 4m
For wiping the cylindrical pillars, we need to wipe the curved surface.
∴Curved surface area of 1 pillar= 2πrh
= 2 x 22/7 x 0.25 x 4 m²
= 2 x 22/7 x 25/100 x 4
= (22/7 x 2) m²
∴Curved surface area of 20 such pillars= 20 x (22/7 x 2) m²
≈125.71 m²
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