Question

20 degree at 20 degree Celsius and 8 litre sample of oxygen exert a pressure of 5 ATM at constant temperature what pressure would be if exert in 2.5 litre vessel at 20 degrees celsius​

Answer 1

Given,

Temperature 1 (T1) = 20°C

= (20+273) K

= 293 K

Volume 1 (V1) = 8 L

Volume 2 (V2) = 2.5 L

Temperature (T2) = 20°C

= 293 K

Pressure 1 (P1) = 5 atm

By Ideal Gas Equation,

P1V1/T1 = P2V2/T2

(5*8)/293 = (2.5P2)/293

40/293 = 2.5P2/293

(40*293) = (2.5P2*293)

11720 = 732.5P2

16 atm = P2

The New Pressure will be 16 atm.

I hope this helps.