Physics, asked by santhuthota0210, 1 month ago

20. Derive s=ut + ½ at2 where the symbols have their usual meaning​

Answers

Answered by lekshminanda06
0

Answer:

Average velocity = u + v /2 . Substitute v = u + at. s = ut + 1/2 at² . Hence proved

Answered by rk5265453
0

Answer:

Suppose a body has an initial velocity 'u' and a uniform acceleration 'a' for time 't' so that its final velocity becomes 'v'. Let the distance travelled by the body in this time be 's'. The distance travelled by a moving body in time 't' can be found out by considering its average velocity. Since the initial velocity of the body is 'u' and its final velocity is 'v', the average velocity is given by

Average velocity =

Explanation:

Initial velocity + Final velocity

That is, Average velocity =

2

u+v

Also, Distance travelled = Average velocity × Time

So, s=(

2

u+v

)×t

From the first equation of motion, we have, v=u+at.

Put this value of v in equation (1), we get:

s=(

2

u+u+at

)×t

or s=

2

(2u+at)×t

or s=

2

2ut+at

2

or s=ut+

2

1

at

2

where, s= distance travelled by the body in time t

u= initial velocity of the body

and a= acceleration

(b) Initial velocity, u=0m/s

Final velocity, v=36km/h=10m/s

Time, t=10min=10×60=600 sec

Acceleration =

time taken

Final velocity - Initial velocity

So, a=

t

v−u

=

600

10−0

=

600

10

m/s

2

=

60

1

m/s

2

=0.016m/s

2

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