Question

20 Derive the following equations of motion for
object with constant acceleration along
a straight line v=-u+at
2 s=ut+1/2at2

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Answer 1

Answer:

Explanation:

1. v -u /t =a

a =v -u /t

at =v -u

v -u =at

v =u + at

2. To find displacement we will find area under the curve.

Displacement = area under the curve

Area of triangle and Area of rectangle

1/2 bh +lb

1/2t (v - u) + tu

ut + 1/2 t(v - u) t /t (multiplying and dividing by t)

ut + 1/2at square

Answer 2

Answer:

Consider a body of mass m, having a initial velocity u. After time t, its velocity becomes v due to uniform acceleration a.

Since, Acceleration=

FinalVelocity−InitialVelocity/Time

Therefore, a= v−u/t

Hence, v=u+at

hope it will help you