Math, asked by kajalchaudhary195, 7 months ago

20. Draw the graph of 3x+2y = 6 . Find the coordinates of the point
where the graph cut the y-axis.​

Answers

Answered by ShreyaKumari5577
0

Answer:

The coordinates of the point where the graph cuts y-axis is (0,3).

Step-by-step explanation:

Given :

Equation  

To find :

The coordinates of the point where the graph cuts y-axis?

Solution :

Plot the equation  with the help of graphing tool.

Refer the attached figure below.

The point cut the y-axis is (3,0).

or The graph cut the y-axis when x=0

So, The coordinates of the point where the graph cuts y-axis is (0,3).

Attachments:
Answered by SarcasticL0ve
4

GivEn Equation:

  • 3x + 2y = 6

⠀⠀⠀

We have to find:

  • Where the graph cut y - axis.

⠀⠀ ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

:\implies\sf 3x + 2y = 6\\ \\

Putting x = 0,

⠀⠀⠀

:\implies\sf 3(0) + 2y = 6\\ \\

:\implies\sf 2y = 6\\ \\

:\implies\sf y = \cancel{ \dfrac{6}{2}}\\ \\

:\implies{\boxed{\frak{\pink{y = 3}}}}\;\bigstar\\ \\

Also,

⠀⠀⠀

Putting x = 2,

⠀⠀⠀

:\implies\sf 3(2) + 2y = 6\\ \\

:\implies\sf 6 + 2y = 6\\ \\

:\implies\sf 2y = 6 - 6\\ \\

:\implies\sf 2y = 0\\ \\

:\implies{\boxed{\frak{\pink{y = 0}}}}\;\bigstar\\ \\

⠀⠀⠀

☯ Now, Plotting the equation 3x + 2y = 6 with the help of graphical tools.

⠀⠀⠀

\setlength{\unitlength}{2.5mm}\begin{picture}(10,10)\multiput(0,0)(2,0){21}{\line(0,1){40}}\multiput(0,0)(0,2){21}{\line(1,0){40}}\linethickness{0.45mm}\put(20,20){\vector(2,0){18}}\put(20,20){\vector(-2,0){18}}\put(20,20){\vector(0,2){18}}\put(20,20){\vector(0,-2){18}}\multiput(19.35,4)(0,4){9}{\line(1,0){1.3}}\multiput(4,19.35)(4,0){9}{\line(0,1){1.3}}\put(20,20){\circle*{1}}\put(20,32){\circle*{1.1}}\put(20,32){\circle{2}}\put(21,33){\sf A(0, 3)}\put(21,37){\sf Y}\put(21,2){\sf Y'}\put(2,21){\sf X'}\put(37,21){\sf X}\put(25,26.8){\bf 3x + 2y = 6}\put(20.5,21){\sf O(0, 0)}\put(28,20){\circle*{1.1}}\put(28,20){\circle{2}}\put(28.5,21.5){\sf O(2, 0)}\linethickness{0.35mm}\qbezier(18,35)(18,35)(30,17)\end{picture}

⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

The graph cut the y - axis when x = 0.

⠀⠀⠀

\therefore\;{\underline{\sf{So,\;the\; co-ordinate\;of\;the\;point\;where\;graph\;cut\;y-axis\;is\; \bf{(0,3)}.}}}

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