Question

20
f
sin (90=0)+cos (90-0) = 12 sin (so-o), show that
(Seno-caso) = √2=sin

​

Answer 1

Answer:

Given

sinA+cosA=

2

sin(90−A)

⇒

2

1

sinA+

2

1

cosA=sin(90−A)

⇒sinA.cos45

∘

+cosA+sin45

∘

=sin(90−A)

⇒(A+45

∘

)=sin(90

∘

−A)

Equating

A+45=90−A

⇒2A=45

∘

⇒A=22

2

1

∘

A=

8

π

∴cotA=cot

8

π

=

2

+1

Step-by-step explanation:

i hope it's helpful to you