Question

20) Factorise the following expression : p2 + 6p+8​

Answer 1

Step-by-step explanation:

${p}^{2} + 6p + 8 \\ {a }^{2} + 2ab + {b }^{2} = ( {a + b)}^{2} \\ {(p + 3)}^{2}$

Answer 2

p² + 6p + 8

p² + 4p + 2p + 8

p ( p + 4 ) + 2 ( p + 2 )

( p + 4 ) ( p + 2 )

$\huge\red{ \boxed{ \small \pink{ \boxed{</p><p></p><p> \boxed{ \therefore{p² + 6p + 8 }}</p><p></p><p> \purple{\boxed{\therefore{p² + 4p + 2p + 8 } }}</p><p></p><p> \green{\boxed{\therefore{p ( p + 4 ) + 2 ( p + 2 )}}}</p><p></p><p> \orange{ \boxed{\therefore{ \implies{( p + 4 ) ( p + 2 )}}}}}</p><p> }}}$