Question

20. Find the equation of the line perpendicular to the line x-2y+3=0 and passing through
the point (1,-2).​

Answer 1

Answer:

2x+y=0 is perpendicular line

Step-by-step explanation:

perpendicular equation for x-2y+3=0

is 2x+y+a=0 which passes through the point (1,-2) then the value of a=0

so the equation is 2x+y=0

Answer 2

Step-by-step explanation:

I solve this question step by step