Question

20 Find
the
roots of the quadeatic eqth 2x² - 2√2 x+1=0
.
using quadeatic formula​

Answer 1

Answer:

x = (1/√2)

Step-by-step explanation:

2x² - 2√2x + 1 = 0

using =>

x = [ -b ± √ { (b)² - 4ac } ] ÷ 2a

a = 2

b = -2√2

c = 1

x = [ -(-2√2) ± { (2√2)² - 4(2)(1) } ] ÷ 2(2)

x = [ 2√2 ± { 8 - 8 } ] ÷ 4

x = [ 2√2 ± 0 ] ÷ 4

x = 2√2 ÷ 4

x = (1/√2)