20. Find the smallest number which when divided by 25,40 and 60 leaves a Remainder 7 in each case.
Answers
Answered by
4
Answer:
LCM of 25,40,60:600. So the number is 600+7=607.
Step-by-step explanation:
607 is the smallest no. which when divided by 25,50 and 60 leaves a remainder of 7
Answered by
2
Answer:
factors of 25 = 5×5
factors of 40 = 2×2×5×2
factors of 60 = 2×2×3×5
LCM = 2³×3×5³
⇒ 600
∴REQUIRED NO: 600+7
⇒607
HOPE IT HELPS :)
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