Question

20. Find the value of 'K for which the equation x² + k (2x + k-1) + 2 = 0 has real and equal
roots.
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Answer 1

p(x)=x²+k(2x+k-1)+2

=>p(x)=x²+2kx+k²-k+2

there are real and equal roots

=> D=0

=>b²-4ac=0

=>(2k)²-4(1)(k²-k+2)=0

=>4k²-4k²+4k-8=0

=>4k-8=0

=>4k=8

=>k=8/4

=>k=2

hence the value of k is 2