Question

20. Find the values of a and b so that the polynomial (x² – 10x² + ax + b) is
exactly divisible by (x - 1) as well as (x - 2).
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Answer 1

Answer:

i think question is little bit wrong

correct equation is(x³ – 10x² + ax + b) not (x² – 10x² + ax + b)

so continue with (x³ – 10x² + ax + b)

x-1=0

x=1

Step-by-step explanation:

now put x=1 in (x³ – 10x² + ax + b)

1³-10(1)²+a(1)+b=0

1-10+a+b=0

a+b=9 ….....(1)

now x-2=0

x=2

put x=2 in (x³ – 10x² + ax + b)

2³-10(2)²+a(2)+b=0

8-40+2a+b=0

2a+b=32.......(2)

by eq(1)(2) usung elemination

2a+b=32

a+b=9

a=23,b= -14