Question

20. Find the values of k for which the quadratic equation 4x² - 3kx + 1 = 0 has real and equal roots.
a.4/3
b.-4/3
c.2/3
d.-2/3
e.2
f.-2
g.none of these

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Answer 1

Answer:

4/3

Step-by-step explanation:

Given quadratic equation = 4k² - 3kx + 1 = 0

d = 0, for real and equal roots.

b² - 4ac = (3k)² - 4 × 3k × 1

0 = 9k² - 12k - 0

0 = 9k² - 12k + 0k +0

0 = 3k(k-4) + 0(k-4)

k = 4/3

Answer 2

Step-by-step explanation:

Given quadratic equation 4x² - 3kx + 1 = 0

Here a = 4, b = -3k and c = 1

Quadratic equation has equal roots ------ ( Given )

then b² - 4ac = 0

9k² - 16 = 0

${k}^{2} = \frac{16}{9}$

$∴ k = ± \frac{4}{3}$