Chemistry, asked by aarishtyagi32, 6 months ago

20 g CaCo3 is treated with 20 g HCL . find limiting reagent and also . find the maximum amount of CO2 form class 11 ​

Answers

Answered by arshadkhan03923
1

Answer:

20 gram of CaCO3 will react with 73/100 *20 g HCl = 14.6 g. HCl only to give CO2. So the limiting reagent is CaCO3. therefore 20 g of CaCO3 will give = 44/100 *20 = 8.8 g CO2.

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