20 g of a magnesium carbonate sample decomposes on heating to give carbon dioxide
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MgCO₃ ⇒ MgO + CO₂
84g 40g
y g 8 g (y is variable used)
y=(84 x 8)/40 = 16.8 g
Percentage purity of MgCO₃ = (16.8 x 100)/20=84%
Hope it helps!
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