Question

20 g of ice melts in a closed copper vessel initially at 20°C, by the time the vessel reaches 0°C. If the specific latent heat of fusion of ice is 340 J/g, and the specific heat capacity of copper is 0.4J/g/k, find the mass of the copper vessel. ​

Answer 1

Answer:

Heat given by water to reach 5oC+ Heat given by copper vessel to reach 5oC= Heat taken by ice to melt at 0oC+ Heat taken by melted ice to reach 5oC

mwcwΔt+mcccΔt=miL+micwδt 

where Δt= change in temperature of water and copper vessel

mw = mass of water = 150g

mc = mass of copper vessel = 100g

mi = mass of ice

cc = specific heat capacity of copper

cw = specific heat capacity of water

L = specific latent heat of fusion of ice

δt = change in temperature of ice

Therefore, [150×4.2×(50−5)]+[100×0.4×(50−5)]=(m×336)+[m×4.2×(5−0)]

(150×4.2×45)+(100×0.4×45)=(m×336)+(m×4.2×m)

28350+1800=336m+21m

357m=30150