Question

20 g. of K3PO4 is dissolved in 350 g of water to come up with 500 ml solution. Calculate the following:
a.Molecular weight ,b.Equivalent weight,c.Molarity,d. Normality,e.Molality

Answer 1

Answer:

Molarity= 0.2M .

Explanation:

Given:-

Mass of NaCl⟶5.85g

Number of moles of NaCl=

58.5

5.85

=0.1

Volume ⟶0.5 litre

Molarity=

Volume(ml)

Numberofmoles

×1000

=

0.5

0.1

Molarity= 0.2M .