20. Given : ED = EC
Prove : AB + AD > BC.
colo
09
B
E
A
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Answered by
0
Answer:
Mention your class 1st. Pic not clear.
Answered by
2
Answer:
Step-by-step explanation:
In ΔBAD: AB+AD > DB --- 1 ( Sum of two sides of Δ is greater than third side)
DB = DE + EB = EC + EB ---- 2 (Given ED=EC)
In Δ BEC: EC + EB > BC -----3
DB> BC ----- 4 From 2&3
AB+AD>DB>BC --- From 1&4
∴ AB + AD > BC
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