20 gm of salt are dissolved in 80 grams of water the concentration of the solution will be
Answers
20 gram of salt are dissolved in 80 gram of water.
we have to find the concentration of the solution.
solution : Therefore are so many methods to find concentration of solution. for instance, mass percent, part per million, mass/volume percent , volume percent, molarity and Molality .
here from data we can only find Molality.
because Molality = no of moles of solute/mass of solvent in kg
here mass of salt = 20g
molar mass of salt , NaCl = 58.5 g/mol
so, molar mass of salt = 20/58.5
mass of solvent ( water) = 80g = 80/1000 kg
now Molality = (20/58.5)/(80/1000)
= (20 × 1000)/(58.5 × 80)
= 4.27 molal
Therefore the concentration of solution is 4.27 molal.
Answer:
20%
Formula:
MaoS (mass of solute) "MoSo"
(Mass of solvent)
MaoS/ (MaoS+MoSo) × 100
Solution:
20g/(20g+80ml)×100
= (20g/100)×100
= 0.2×100
=20
= add percentage (20%)
Q:Why is there a hundred?
A: because it is solving for the "percentage" per-cent (100)