Question

20 gram of a mixture of Na2 CO3, NaHCO3 and NaCl when heated produce 1.12 litre CO2 at STP if the starting mixture is reacted with HCl ,0.3 moles of HCL are required for complete reaction find percentage of NaCl in the mixture .​

Answer 1

Answer:

Sodium bicarbonate decomposes in

the following manner.

2NaHCO

3

→Na

2

CO

3

+H

2

O+CO

2

Sodium Carbonate is stable and

doesn't dissociate upon normal

heating.

Vol. of CO

2

=224ml

22.4Ltr=1mole

So moles of CO

2

=0.224/22.4=0.01mole

0.01mole=44×0.01g=0.44g

1 mole CO

2

is procured by 2 mole NaHCO

3

∴ Moles of NaHCO

3

=2×0.01=0.02

=0.02×84=1.689

% age =

Totalmass

mass

×100=

2

1.68

×100=84%

solution