Question

20 grams of the helium effuse from a pin in 20 s then in similar condition calculate the weight of so3 which is going to effuse through same pin hole in 50 seconds​

Answer 1

Explanation:

Given,

Time taken for oxygen diffusion=10 sec

Also pressure,volume,temperature is constant.

Molar mass of oxygen=32g/mole

Molar mass of sulphur dioxide=64g/mole

According to graham's law of diffusion/effusion

r∝

M

1

r=rate of diffusion

M=molar mass

r

SO

2

r

O

2

=

M

O

2

M

SO

2

since,

r=V/T,r∝

t

1

t

O

2

t

SO

2

=

M

O

2

M

SO

2

10

t

SO

2

=

32

64

t

SO

2

=14.14