Question

20. If log 3 = 0.4771 find log 729º9-1 x 27-473
1:​

Answer 1

Step-by-step explanation:

Given log2=0.3010 and log3=0.4771

Given log2=0.3010 and log3=0.4771log12=log(4×3)

Given log2=0.3010 and log3=0.4771log12=log(4×3) =log4+log3

Given log2=0.3010 and log3=0.4771log12=log(4×3) =log4+log3 =log2

Given log2=0.3010 and log3=0.4771log12=log(4×3) =log4+log3 =log2 2

Given log2=0.3010 and log3=0.4771log12=log(4×3) =log4+log3 =log2 2 +log3

Given log2=0.3010 and log3=0.4771log12=log(4×3) =log4+log3 =log2 2 +log3 =2log2+log3

Given log2=0.3010 and log3=0.4771log12=log(4×3) =log4+log3 =log2 2 +log3 =2log2+log3Substituting the values

Given log2=0.3010 and log3=0.4771log12=log(4×3) =log4+log3 =log2 2 +log3 =2log2+log3Substituting the values =2×0.3010+0.4771

Given log2=0.3010 and log3=0.4771log12=log(4×3) =log4+log3 =log2 2 +log3 =2log2+log3Substituting the values =2×0.3010+0.4771 =0.602+0.4771

Given log2=0.3010 and log3=0.4771log12=log(4×3) =log4+log3 =log2 2 +log3 =2log2+log3Substituting the values =2×0.3010+0.4771 =0.602+0.4771 =1.0791

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