Question

20. If one angle of a triangle is 56' and
the difference of the other two
angles is 20', then find the other two
angles.
*​

Answer 1

$\sf{\bold{\purple{\star{\underline{\underline{given}}}}}}$

One angle of a triangle = 56°

Diff. btw other 2 angles = 20°

⠀⠀⠀⠀

$\sf{\bold{\purple{\star{\underline{\underline{To\: find}}}}}}⋆$

Other 2 unknown angles = ??

⠀⠀⠀⠀

$\sf{\bold{\purple{\star{\underline{\underline{Solution}}}}}}$

Let the angle be x

⠀⠀⠀⠀

Other angle = x + 20

⠀⠀⠀⠀

$\sf{\star{\boxed{\orange{\frak{ Sum\: of \: all \: all \: angles\: of \: triangle = \: 180}}}}}$

$\sf : \implies\:{\frak{ x + x + 20+ 56 = 180 }}$

$\sf : \implies\:{\frak{ x + x + 76 = 180 }}:⟹x+x+76=180$

$\sf : \implies\:{\frak{ 2x + 76 = 180 }}:⟹2x+76=180$

$\sf : \implies\:{\frak{ 2x = 180 - 76 }}:⟹2x=180−76$

$\sf : \implies\:{\frak{ 2x = 104 }}:⟹2x=104$

$</p><p> \sf : \implies\:{\frak{ x = \dfrac{104}{2}}}:⟹x= \frac{2}{104} </p><p>$

$\sf : \implies\:{\frak{ x = 52 }}:⟹x=52$

$\sf{\star{\boxed{\blue{\frak{ x = 52 }}}}}⋆ </p><p>x=52$

putting value of x in angles

⠀⠀⠀⠀

1st unknown angle

$= x = \sf{\dag{\boxed{\pink{\frak{ 52 }}}}}† </p><p>52$

2nd unknown angle

$= x + 20 = 52 + 20 = \sf{\dag{\boxed{\pink{\frak{ 72 }}}}}† </p><p>72</p><p>$

hope it helps........

Answer 2

$\huge \red {\underbrace \mathfrak{Answer :}}$

Given:-

• One angle of a triangle = 56°
• Different between other 2 angles = 20°

To Find:-

• Other 2 unknown angles = ?

$\huge {\fbox \red{Solution :}}$

• Let the angle be x
• Other angle = x + 20

Sum of all the angles of triangles = 180°

→ x + x + 20 + 56 = 180

→ x + x + 76 = 180

→ 2x + 76 = 180

→ 2x = 180 - 76

→ 2x = 104

→ x = 104/2

→ X = 52

• putting value of x in angles

1st unknown angle = x = +52

2nd unknown angle = x + 20 = 52 +20 = +72

Step-by-step explanation:

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