Question

20. If x is given as below the x is equal to
let x be
$\sqrt{6 + \sqrt{6 + \sqrt{6 + upto \infty } } }$

3, -4
- 2,5

3,-2
none of these​

Answer 1

20. If x is given as below the x is equal to

let x be

$\sqrt{6 + \sqrt{6 + \sqrt{6 + upto \infty } } }$

3, -4

- 2,5

3,-2

none of these

Answer 2

Answer:

3, -2

Step-by-step explanation:

x = √6+√6+√6+....up to infinity

x= √6+x .....(infinity - 1 = infinity)

x2 = 6+x

x2 - x - 6 = 0

x2 -3x +2x - 6 = 0

x(x-3)+2(x-3)= 0

(x-3)(x+2)= 0

x = 3, -2