Question

20. If x - y = xy÷p_q
find the value of x when y = 2, p = 5 and q = 6. ​

Answer 1

Step-by-step explanation:

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Answer 2

First substitute the values:

x-2 =X(2)/5-6

x-2 = 2x/-1

x-2 = -2x

Bring x to the other side:

-2 = -2x-x

-2 = -3x

Reverse the equation:

-3x = -2

Now put it in a fraction form:

x = 2/3

Answer:

x = 2/3