Question

20.

In a circle of radius 10 cm, the length of chord whose distance is 6 cm from the centre is

a)4 cm

b)5 cm

c)8 cm

d)16 cm​

please help

Answer 1

Let's take a circle with centre O and radius OA = 10 cm .

The chord starts from 6 cm below the centre .

so , distance of OB from chord BA is 6 cm .

Length of AB = Pythagoras theorem for triangle AOB .

$\sf{\sqrt{{(10)^2}-{(6)^2}}} = \sf{AB} \\\\ \sf{\sqrt{100-36}} = \sf{AB} \\\\ \sf{\sqrt{64}} = AB \\\\ \sf{AB=8}$

As we know , the perpendicular drawn from a chord bisects the chord , so , the total length of the chord is 16 cm .

Answer 2

answer:

d)16 cm

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