Question

20. In Fig. 10.115, AB || CD || EF and GH || KL. Find angle hkl​

Answer 1

Answer:

145 is a correct answer

Step-by-step explanation:

let us extend the line GH to n such that it's intersect the line AB at M

AB ||CD and GM is transversal

= the angle AMH =angle CHG =60° ( corresponding Angle)

angle NMB = angle AMH =60° ( vertically opposite angle )

AB ||CD and HK is a transversal

=the angle AKH =angle KHD =25° ( alternative interior angle )

NM ||KL and KM is transversal

The angle NMK = angle LKB=60°. ( corresponding Angle )

=angle LKM =180°-angle KLB. (linear pair)

= angle LKM =180-60= 120°

=angle HKL = angle HKA +angle AKL

=angle HKL =25+120=145