Question

20
In the fig. given if R 2 = 2 R1
and if they are
Connected in
series to a 4V batter find potential difference acrossR1andR2
​

Answer 1

Explanation:

as given in the circuit, current is given by I

⇒I=

R

eq

V

⇒R

eq

=R

2

+

R

1

+R

v

R

1

R

v

where R

v

is the resistance of the given voltmeter

⇒R

eq

=880+

200+300

200×300

=1000Ω

⇒I=

R

eq

V

=

1000

40

=0.04volt

Reading of volmeter = potential difference =

⇒I×(

R

1

+R

v

R

1

×R

v

)

⇒I×

200+300

200×300

)=0.04×120=4.8volt