20. In the figure given below, find the value of AC. A 16 cm 90° B C 30 cm what si answer
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Answer:
Given: D=90°,AB=16cm,BC=12cm and CA=6cm
ADC is a right triangle.
So, AC2=AD2+CD2 [Pythagoras theorem]
62=AD2+CD2…..(i)
ABD is also a right triangle.
So, AB2=AD2+BD2 [Pythagoras theorem]
162=AD2+(BC+CD)2
162=AD2+(12+CD)2
256=AD2+144+24CD+CD2
256−144=AD2+CD2+24CD
AD2+CD2=112−24CD
62=112−24CD [from (i)]
36=112−24CD
24CD=112−36
24CD=76
CD=
Explanation:
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