Math, asked by moinkhanairforce, 4 days ago

20)-In triangle ABC, DE parallel to BC so that AD-2.4 cm, AE=3.2 cm and EC-4.8 cm, Then find AB=?
d)
a) 3.6 cm
b) 6 cm
c) 6.4 cm
d) 7.2 cm​

Answers

Answered by karan7160
0

Answer:

6 cm

Step-by-step explanation:

We have,

AD=2.4 cm

AE=3.2 cm

EC=4.8 cm

AB=?

Since,

DE∣∣BC

Therefore,

AB

AD

=

AC

AE

AB

2.4

=

AE+EC

3.2

AB

2.4

=

3.2+4.8

3.2

AB

24

=

8

32

AB

24

=4

AB=6 cm

Hence, this is the answer.

Answered by Himnishsoni
1

Answer:

We have,

AD=2.4 cm

AE=3.2 cm

EC=4.8 cm

AB=?

Since,

DE∣∣BC

Therefore,

AD/AB = AE/AC

2.4/AB = 3.2/AE + EC

2.4/AB = 3.2/3.2 +4.8

24/AB = 32/8​  

​24/AB = 4

AB=6 cm

Step-by-step explanation:

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