Question

20 J work is done to carry 10 C charges when current flowing in circuit is 1 ampere find resistance ​

Answer 1

Answer:

2 Ohm

Explanation:

By Relation

Work Done = Charge × Potential Difference

Work Done = 20 J

Charge = 10 C

Let Potential Difference be V

20 = 10 × V

V = 2 Volts

Now Using Ohm's Law

V = i × R

Where,

V = 2 Volts

i =  1 Ampere

So,

R = V ÷ i

R = 2/1

R = 2 Ohms

Answer 2

Given

➠ Work done to carry charge = 20 J

➠ Charge flowing = 10 C

➠ Current in circuit = 1 A

To find

➠ Resistance of circuit

Solution

Now we know the formula :

⎆ V = W/Q

Where,

• V denotes potential difference
• W denotes work done
• Q denotes charge

Substituting values,

⇒ Potential difference = 20 J/10 C

⇒ Potential difference = 2 v

∴ Potential difference of circuit = 2 volts.

Now we know Ohm's law :

⎆ V = I * R

Where,

• V denotes potential difference
• I denotes current
• R denotes resistance

Substituting values,

⇒ 2 = 1 * Resistance

⇒ Resistance = 2

⇒ Resistance = 2Ω

∴ Resistance of circuit = 2 Ω [Answer]