20 joule work is done in moving a charge 'q' between two points having potential difference of 12 volts find the value of charge
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Given,
Work Done (W) = 20 J
Potential Difference (V) = 12 V
∴ V = W/Q
= 12 = 20/Q
= 12Q = 20
= Q = 1.67 C
The Charge is 1.67 C.
I hope this helps.
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