Question

20 L of a mixture contains alcohol and water in the ratio 2:3. If 4L of water is
mixed in it, the percentage of alcohol in the new mixture will be​

Answer 1

Answer:

$20 \div 8 \times 4 =$

10 ltr

Step-by-step explanation:

2x + 3x = 20ltr (given)

5x=20ltr

x =20/5

x =4

so, amount of alcohal in 20 ltr mixture =4*2 =8

so, in 4 ltr amount of alcohal = 20/8*4 = 10 ltr