20 man complete one-third of a piece of work in 20 days. How many more men should be employed to finish the rest of the work in 25 more days
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Answer:
12 men
Step-by-step explanation:
Given,
M1 = 20
M2 = 20 + x
W1 = 1/3
W2 = 1 - 1/3 =2/3
D1 =20 and D2 = 25
According to the formula, M1D1W2 = M2D2W1
20 x20 x (2/3) =(20 + x) x 25 x (1/3)
20 x 20 x (2/3)= (20 + x) x 25/3
= > 16 x 2 = 20 + x
x = 32 - 20 = 12
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