Math, asked by joshiankita621, 10 months ago

20 men can do a job in 10 days, working 8 hours a day, If women are 33.33% more efficient than men, how many woman will it take to finish the same job in 10 days. Working 6 hours a day ?


Alternate Method:
(M x D1 x H1) = (W x D2 x H2)
Here W=1.3333M = (4/3)M
=> (20 x 10 x 8) = (W x 10 x 6) x (4/3)
=> W = 20


Can somebody explain how 2nd eq. multiply by 4/3

((W x 10 x 6) x (4/3))​

Answers

Answered by HeAvEnPrlnCesS
4

Total number of hours worked by men = 10 x 8 = 80

Hence, work done by 20 men in 1 hour = 1/80

Work done by 1 man in one hour = 1/1600

Since, women are 33.33% more efficient, work done by one woman in 1 hour = 1.3333/1600

Let w be the required number of women.

Then,

w * (1.3333/1600) * 6 * 10 = 1

Or, w = 1600/(60 x 1.3333)

or, w = 20

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