20 men can do a job in 10 days, working 8 hrs a day if women is 33.33% more efficient than men. how many women will it take to finish the same job in 10days working 6 hrs a day? a) 10
Answers
Answered by
41
✌✌✌
__________________________________
Answer: 20
Solution:
Total men hours of work = 20 × 10 × 8 = 1600
So 1 man, 1 hr work = 1/1600
As woman is 33.33% more efficient, so 1 woman,
1 hr work=(133.33/100) x (1/1600)=1.3333/1600
So 10 days work of 1 woman working 6
=10 × 6 × (1.3333/1600)
= 1/20
Hence 20 women are required.
__________________________________
Thanks for the question!
♥♥♥
__________________________________
Answer: 20
Solution:
Total men hours of work = 20 × 10 × 8 = 1600
So 1 man, 1 hr work = 1/1600
As woman is 33.33% more efficient, so 1 woman,
1 hr work=(133.33/100) x (1/1600)=1.3333/1600
So 10 days work of 1 woman working 6
=10 × 6 × (1.3333/1600)
= 1/20
Hence 20 women are required.
__________________________________
Thanks for the question!
♥♥♥
Answered by
13
❤❤Here is your answer ✌ ✌
Total men hours of work↩
➡ 20 × 10 × 8 = 1600hours
So ,
1 man, 1 hr work = 1/1600 hours
As woman is [33.33%] more efficient,
so
1 woman,
1 hr work=(133.33/100) x (1/1600)=1.3333/1600hours•
So ,
10 days work of 1 woman working 6
➡10 × 6 × (1.3333/1600)
➡ 1/20hour
Hence
Total men hours of work↩
➡ 20 × 10 × 8 = 1600hours
So ,
1 man, 1 hr work = 1/1600 hours
As woman is [33.33%] more efficient,
so
1 woman,
1 hr work=(133.33/100) x (1/1600)=1.3333/1600hours•
So ,
10 days work of 1 woman working 6
➡10 × 6 × (1.3333/1600)
➡ 1/20hour
Hence
Similar questions