Question

20 men can do a piece of workin 16 days.if the same workhas been completed with in 20 days,how many men should be removed?

Answer 1

Step-by-step explanation:

20 men complete a work in………. 40 days.

20 men complete a work in………. 40 days.1 man can the same work. ….20*40= 800 days.

20 men complete a work in………. 40 days.1 man can the same work. ….20*40= 800 days.4 men left the work after some days.

20 men complete a work in………. 40 days.1 man can the same work. ….20*40= 800 days.4 men left the work after some days.That's (20–4) = 16 men completes…48 days.

20 men complete a work in………. 40 days.1 man can the same work. ….20*40= 800 days.4 men left the work after some days.That's (20–4) = 16 men completes…48 days.1 man could do left work in 16*48= 768 days. Then.... 800–768 = 32 days equivalent work was completed by 1 man.

20 men complete a work in………. 40 days.1 man can the same work. ….20*40= 800 days.4 men left the work after some days.That's (20–4) = 16 men completes…48 days.1 man could do left work in 16*48= 768 days. Then.... 800–768 = 32 days equivalent work was completed by 1 man.Then for 4 men could do the same work in 32/4= 8 days. So after 8 days 4 men left the work is the answer. (This unitary method is applied from the point of view of a labour contractor.)

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