20 men complete 1/3 part of a piece of work in 20 days .how many more men should be deployed to complete the remaining work in 25 more days?
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you first of all multiply 20 and 1/3 and then from obtain result compare with 25 days and you get your successive result
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20 men ----- 20 days ----- 1/3 work
20 men ----- 5 days ----- 1/12 work
now
20 men completes 1/3 work in 20 days
in next 25 days these men complets another 1/3 + 1/12 work
= 5/12 work
so original batch completes
1/3 +5/12 = 3/4 work
so another 1/4 work remains
now ,
20 men ----- 1/12 work ------ 5 days
60 men ------ 1/4 work -------- 5 days
12 men ------ 1/4 work -------- 25 days
so extra 12 men requires
20 men ----- 5 days ----- 1/12 work
now
20 men completes 1/3 work in 20 days
in next 25 days these men complets another 1/3 + 1/12 work
= 5/12 work
so original batch completes
1/3 +5/12 = 3/4 work
so another 1/4 work remains
now ,
20 men ----- 1/12 work ------ 5 days
60 men ------ 1/4 work -------- 5 days
12 men ------ 1/4 work -------- 25 days
so extra 12 men requires
pravinsir:
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