20 men take 10 days to complete a job working 12 hours a day find the number of men required to complete twice as large in 30 days working 8 hours a day?
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Days Men Hours
10 20 12
30 x 8
Ratio of days = 10 : 30 = 1 : 3
Ratio of Hours = 12 : 8 = 3 : 2
Ratio of men = 20 : x
Compound ratio of 1 :3 and 3 : 2 is
1 : 3 :: 3 : 2 = 1×3 : 3×2 = 3 : 6 = 1 : 2
Ratio of men is inversely proportional to Days and Hours
20 : x = 2 : 1
2x = 20
x = 10
10 men required
10 20 12
30 x 8
Ratio of days = 10 : 30 = 1 : 3
Ratio of Hours = 12 : 8 = 3 : 2
Ratio of men = 20 : x
Compound ratio of 1 :3 and 3 : 2 is
1 : 3 :: 3 : 2 = 1×3 : 3×2 = 3 : 6 = 1 : 2
Ratio of men is inversely proportional to Days and Hours
20 : x = 2 : 1
2x = 20
x = 10
10 men required
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