Question

20 micro coulomb is placed inside a closed surface then flux linked with a surface is fie . if 80 micro coulomb charge is put inside the surface then change in flux is​

Answer 1

Answer:

The change in flux is 4 times of initial flux.

Explanation:

Given that,

20 micro C is placed inside a closed surface then flux linked with a surface is $\phi$.

If 80 micro C is put inside the surface then

We need to calculate the initial flux

Using formula of flux

$\phi=\dfrac{q}{\epsilon_{0}}$

The Initial flux is

$\phi_{i}=\dfrac{20\times10^{-6}}{\epsilon_{0}}$

The final flux is

$\phi_{f}=\dfrac{(20+80)\times10^{-6}}{\epsilon_{0}}$

We need to calculate the change in flux

$\Delta \phi=\phi_{f}-\phi_{i}$

Put the value into the formula

$\Delta\phi=\dfrac{100\times10^{-6}}{\epsilon_{0}}-\dfrac{20\times10^{-6}}{\epsilon}$

$\Delta \phi=\dfrac{80\times10^{6}}{\epsilon_{0}}$

$\Delta \phi=4\times\phi_{i}$

Hence, The change in flux is 4 times of initial flux.