Question

20 ml of 0.05 n hcl is mixed withb10 ml of 0.1 n naoh. find ph

Answer 1

let the normality of HCL that is N1= 0.05n
and the volume of HCL that is V1 be 20 ml
the normality of NAOH i.e is N2=0.1n
the volume of NAOH I.e V2=0.1
we know that,
N1.V1 - N2.V2=N(V1.V2)
0.05×20-0.1×10=N(20+10)
1-1=N(30)
0=N(30)
N=0
therefore the normality of resulting solution is 0 and the the pH of the solution will be neutral