20 ml of 0.1 m h2so4 is added to 30 ml of 0.2 m nh4oh then calculate ph of resultant solution . (given that pkb of nh4oh is 4.7)
Answers
Answered by
55
The pH of the solution will be 9.777
Explanation :
we know that pH of a solution is given by;
pH = 14-[pkb +log(acid/base)]
moles equivalent of H₂SO₄ = 20 x 0.1 = 2
moles equivalent of NH₄OH = 30 x 0.2 = 6
=> pH = 14 - [ 4.7 + log(2/6)]
=> pH = 14 - [ 4.7 - log3]
=> pH = 14 - [ 4.7 -0.477 ]
= 14 - 4.223
=> pH = 9.777
Hence the pH of the solution will be 9.777
Answered by
8
Answer:
The ph of the solution will be 9.0
Explanation:
we know that pH of a solution is given by;
pH = 14-[pkb +log(acid/base)]
moles equivalent of H₂SO₄ = 20 x 0.1 x2 = 4
moles equivalent of NH₄OH = 30 x 0.2 = 6
=> pH = 14 - [ 4.7 + log(4/2)]
pH = 14 - [ 4.7 + 0.3 ]
pH = 14 - 5
pH = 9.0
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