Question

20 ml of 0.2 m al2(so4)3 is mixed with 20 ml of 0.6 m bacl2 calculate the concentration of each ion in the solution

Answer 1

Answer:

Total amount of chloride ion in solution = 2*20mL*6.6mmol/mL = 264 mmol

( We have assumed that no chloride ion is bound to the captions Ba++ and Al+++ which are also present in solution. This is not exactly correct because ion-pairs are also present in the solution.)

Total volume of solution= 20 mL + 20 mL = 40 mL

Concentration (molarity) = 264 mmol/40 mL =6.6 M

Hope it helps